Optimal. Leaf size=255 \[ -\frac {2 d p^2 x^{1-n} (f x)^{-1+2 n}}{e n}+\frac {p^2 x^{1-2 n} (f x)^{-1+2 n} \left (d+e x^n\right )^2}{4 e^2 n}+\frac {2 d p x^{1-2 n} (f x)^{-1+2 n} \left (d+e x^n\right ) \log \left (c \left (d+e x^n\right )^p\right )}{e^2 n}-\frac {p x^{1-2 n} (f x)^{-1+2 n} \left (d+e x^n\right )^2 \log \left (c \left (d+e x^n\right )^p\right )}{2 e^2 n}-\frac {d x^{1-2 n} (f x)^{-1+2 n} \left (d+e x^n\right ) \log ^2\left (c \left (d+e x^n\right )^p\right )}{e^2 n}+\frac {x^{1-2 n} (f x)^{-1+2 n} \left (d+e x^n\right )^2 \log ^2\left (c \left (d+e x^n\right )^p\right )}{2 e^2 n} \]
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Rubi [A]
time = 0.13, antiderivative size = 255, normalized size of antiderivative = 1.00, number of steps
used = 10, number of rules used = 9, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.375, Rules used = {2506, 2504,
2448, 2436, 2333, 2332, 2437, 2342, 2341} \begin {gather*} \frac {x^{1-2 n} (f x)^{2 n-1} \left (d+e x^n\right )^2 \log ^2\left (c \left (d+e x^n\right )^p\right )}{2 e^2 n}-\frac {d x^{1-2 n} (f x)^{2 n-1} \left (d+e x^n\right ) \log ^2\left (c \left (d+e x^n\right )^p\right )}{e^2 n}-\frac {p x^{1-2 n} (f x)^{2 n-1} \left (d+e x^n\right )^2 \log \left (c \left (d+e x^n\right )^p\right )}{2 e^2 n}+\frac {2 d p x^{1-2 n} (f x)^{2 n-1} \left (d+e x^n\right ) \log \left (c \left (d+e x^n\right )^p\right )}{e^2 n}+\frac {p^2 x^{1-2 n} (f x)^{2 n-1} \left (d+e x^n\right )^2}{4 e^2 n}-\frac {2 d p^2 x^{1-n} (f x)^{2 n-1}}{e n} \end {gather*}
Antiderivative was successfully verified.
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Rule 2332
Rule 2333
Rule 2341
Rule 2342
Rule 2436
Rule 2437
Rule 2448
Rule 2504
Rule 2506
Rubi steps
\begin {align*} \int (f x)^{-1+2 n} \log ^2\left (c \left (d+e x^n\right )^p\right ) \, dx &=\left (x^{1-2 n} (f x)^{-1+2 n}\right ) \int x^{-1+2 n} \log ^2\left (c \left (d+e x^n\right )^p\right ) \, dx\\ &=\frac {\left (x^{1-2 n} (f x)^{-1+2 n}\right ) \text {Subst}\left (\int x \log ^2\left (c (d+e x)^p\right ) \, dx,x,x^n\right )}{n}\\ &=\frac {\left (x^{1-2 n} (f x)^{-1+2 n}\right ) \text {Subst}\left (\int \left (-\frac {d \log ^2\left (c (d+e x)^p\right )}{e}+\frac {(d+e x) \log ^2\left (c (d+e x)^p\right )}{e}\right ) \, dx,x,x^n\right )}{n}\\ &=\frac {\left (x^{1-2 n} (f x)^{-1+2 n}\right ) \text {Subst}\left (\int (d+e x) \log ^2\left (c (d+e x)^p\right ) \, dx,x,x^n\right )}{e n}-\frac {\left (d x^{1-2 n} (f x)^{-1+2 n}\right ) \text {Subst}\left (\int \log ^2\left (c (d+e x)^p\right ) \, dx,x,x^n\right )}{e n}\\ &=\frac {\left (x^{1-2 n} (f x)^{-1+2 n}\right ) \text {Subst}\left (\int x \log ^2\left (c x^p\right ) \, dx,x,d+e x^n\right )}{e^2 n}-\frac {\left (d x^{1-2 n} (f x)^{-1+2 n}\right ) \text {Subst}\left (\int \log ^2\left (c x^p\right ) \, dx,x,d+e x^n\right )}{e^2 n}\\ &=-\frac {d x^{1-2 n} (f x)^{-1+2 n} \left (d+e x^n\right ) \log ^2\left (c \left (d+e x^n\right )^p\right )}{e^2 n}+\frac {x^{1-2 n} (f x)^{-1+2 n} \left (d+e x^n\right )^2 \log ^2\left (c \left (d+e x^n\right )^p\right )}{2 e^2 n}-\frac {\left (p x^{1-2 n} (f x)^{-1+2 n}\right ) \text {Subst}\left (\int x \log \left (c x^p\right ) \, dx,x,d+e x^n\right )}{e^2 n}+\frac {\left (2 d p x^{1-2 n} (f x)^{-1+2 n}\right ) \text {Subst}\left (\int \log \left (c x^p\right ) \, dx,x,d+e x^n\right )}{e^2 n}\\ &=-\frac {2 d p^2 x^{1-n} (f x)^{-1+2 n}}{e n}+\frac {p^2 x^{1-2 n} (f x)^{-1+2 n} \left (d+e x^n\right )^2}{4 e^2 n}+\frac {2 d p x^{1-2 n} (f x)^{-1+2 n} \left (d+e x^n\right ) \log \left (c \left (d+e x^n\right )^p\right )}{e^2 n}-\frac {p x^{1-2 n} (f x)^{-1+2 n} \left (d+e x^n\right )^2 \log \left (c \left (d+e x^n\right )^p\right )}{2 e^2 n}-\frac {d x^{1-2 n} (f x)^{-1+2 n} \left (d+e x^n\right ) \log ^2\left (c \left (d+e x^n\right )^p\right )}{e^2 n}+\frac {x^{1-2 n} (f x)^{-1+2 n} \left (d+e x^n\right )^2 \log ^2\left (c \left (d+e x^n\right )^p\right )}{2 e^2 n}\\ \end {align*}
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Mathematica [A]
time = 0.08, size = 140, normalized size = 0.55 \begin {gather*} \frac {x^{-2 n} (f x)^{2 n} \left (2 d^2 p^2 \log ^2\left (d+e x^n\right )+2 d^2 p \log \left (d+e x^n\right ) \left (3 p-2 \log \left (c \left (d+e x^n\right )^p\right )\right )+e x^n \left (p^2 \left (-6 d+e x^n\right )+2 p \left (2 d-e x^n\right ) \log \left (c \left (d+e x^n\right )^p\right )+2 e x^n \log ^2\left (c \left (d+e x^n\right )^p\right )\right )\right )}{4 e^2 f n} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.07, size = 0, normalized size = 0.00 \[\int \left (f x \right )^{-1+2 n} \ln \left (c \left (d +e \,x^{n}\right )^{p}\right )^{2}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [A]
time = 0.30, size = 200, normalized size = 0.78 \begin {gather*} -\frac {e p {\left (\frac {2 \, d^{2} f^{2 \, n} \log \left (\frac {e x^{n} + d}{e}\right )}{e^{3} n} + \frac {e f^{2 \, n} x^{2 \, n} - 2 \, d f^{2 \, n} x^{n}}{e^{2} n}\right )} \log \left ({\left (e x^{n} + d\right )}^{p} c\right )}{2 \, f} + \frac {\left (f x\right )^{2 \, n} \log \left ({\left (e x^{n} + d\right )}^{p} c\right )^{2}}{2 \, f n} + \frac {{\left (2 \, d^{2} f^{2 \, n} \log \left (e x^{n} + d\right )^{2} + e^{2} f^{2 \, n} x^{2 \, n} - 6 \, d e f^{2 \, n} x^{n} - 2 \, {\left (2 \, f^{2 \, n} \log \left (e\right ) - 3 \, f^{2 \, n}\right )} d^{2} \log \left (e x^{n} + d\right )\right )} p^{2}}{4 \, e^{2} f n} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.42, size = 202, normalized size = 0.79 \begin {gather*} \frac {{\left ({\left (p^{2} e^{2} - 2 \, p e^{2} \log \left (c\right ) + 2 \, e^{2} \log \left (c\right )^{2}\right )} f^{2 \, n - 1} x^{2 \, n} - 2 \, {\left (3 \, d p^{2} e - 2 \, d p e \log \left (c\right )\right )} f^{2 \, n - 1} x^{n} - 2 \, {\left (d^{2} f^{2 \, n - 1} p^{2} - f^{2 \, n - 1} p^{2} x^{2 \, n} e^{2}\right )} \log \left (x^{n} e + d\right )^{2} + 2 \, {\left (2 \, d f^{2 \, n - 1} p^{2} x^{n} e - {\left (p^{2} e^{2} - 2 \, p e^{2} \log \left (c\right )\right )} f^{2 \, n - 1} x^{2 \, n} + {\left (3 \, d^{2} p^{2} - 2 \, d^{2} p \log \left (c\right )\right )} f^{2 \, n - 1}\right )} \log \left (x^{n} e + d\right )\right )} e^{\left (-2\right )}}{4 \, n} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int {\ln \left (c\,{\left (d+e\,x^n\right )}^p\right )}^2\,{\left (f\,x\right )}^{2\,n-1} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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